find value of a sec²A-9 tan²A
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Answered by
1
Answer:
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Answered by
9
Step-by-step explanation:
We have, 9sec
2
A−9tan
2
A
Let r=9sec
2
A−9tan
2
A
r=9(sec
2
A−tan
2
A)
We know that
sec
2
A−tan
2
A=1
Therefore,
r=9×1=9
Hence, this is the answer.
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