Question

Find value of b if the value of bx+3(2x-7)=16 at x=3

Answer 1

$\large{\implies{Answer}}$

$bx + 3(2x - 7) = 16 \\ b(3) + 3(2(3) - 7) = 16 \\ 3b + 3(6 - 7) = 16 \\ 3b + 3( - 1) = 16 \\ 3b - 3 = 17 \\ 3b = 17 + 3 \\ 3b = 20 \\ b = \frac{20}{3}$

Answer 2

Here is your answer....