find value of b in 3x^2+bx+15 at x=1/3
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Answer:
b= -16
Step-by-step explanation:
p(x)=3x²+bx+15
substitute x=1/3
0=3(1/3)²+b/3+15/3
0=3(1/9)+b/3+15/3
0=1/3+b/3+15/3
0=1+b+15/3
0=16+b
b= -16
omparab8:
why did you put there 15/3?
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