Question

Find value of cos θ with respect to the triangle, such that the sides opposite and adjacent to θ measure 6 units and 8 units respectively. ​

Answer 1

Solution:

Given: The sides opposite and adjacent sides to θ are 6 units and 8 units respectively. ​

To find: cos θ

We know that,

• cos θ = (adjacent side) / (hypotenuse)

So, to find the value of cos θ we need to find hypotenuse first...

• We can use Pythagoras's Theorem to find hypotenuse when opposite and adjacent sides to θ are given.

∵ $Hypotenuse = \sqrt[2]{(Opposite Side)^2+(Adjacent Side)^2}$

⇒ $Hypotenuse = \sqrt[2]{(6)^2+(8)^2}$

⇒ $Hypotenuse = \sqrt[2]{36+64}$

⇒ $Hypotenuse = \sqrt[2]{100}$

⇒ $Hypotenuse = \sqrt[]{10^2}$

→ We get, Hypotenuse = 10 units.

• cos θ = (adjacent side) / (hypotenuse)

• Adjacent side = 8 units; Hypotenuse = 10 units

∴ cos θ = (8) / (10) = 4/5

Answer:

→ cos θ = 4/5

______________________________________________________

Thank you, please mark as Brainliest!

⇒ Anagh :)

Answer 2

Solution:

Given: The sides opposite and adjacent sides to θ are 6 units and 8 units respectively.

To find: cos θ

We know that,

cos θ = (adjacent side) / (hypotenuse)

So, to find the value of cos θ we need to find hypotenuse first...

We can use Pythagoras's Theorem to find hypotenuse when opposite and adjacent sides to θ are given.

∵ Hypotenuse = \sqrt[2]{(Opposite Side)^2+(Adjacent Side)^2}Hypotenuse=

2

(OppositeSide)

2

+(AdjacentSide)

2

⇒ Hypotenuse = \sqrt[2]{(6)^2+(8)^2}Hypotenuse=

2

(6)

2

+(8)

2

⇒ Hypotenuse = \sqrt[2]{36+64}Hypotenuse=

2

36+64

⇒ Hypotenuse = \sqrt[2]{100}Hypotenuse=

2

100

⇒ Hypotenuse = \sqrt[]{10^2}Hypotenuse=

10

2

→ We get, Hypotenuse = 10 units.

cos θ = (adjacent side) / (hypotenuse)

Adjacent side = 8 units; Hypotenuse = 10 units

∴ cos θ = (8) / (10) = 4/5

Answer:

→ cos θ = 4/5

______________________________________________________

Thank you, please mark as Brainliest!

⇒ Anagh :)