Find value of cosec2 67- tan2 23/ sin2 17 + sin2 73
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(cosec²67°- tan²23°)/(sin²17° + sin²73°)
=[cosec²(90°-23°) -tan²23°]/[sin²(90°-73°) +sin²73°]
=(sec²23° - tan²23°)/(cos²73° + sin²73°)
=1/1
=1
=[cosec²(90°-23°) -tan²23°]/[sin²(90°-73°) +sin²73°]
=(sec²23° - tan²23°)/(cos²73° + sin²73°)
=1/1
=1
kvnmurty:
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Answered by
2
Answer:
(cosec²67°- tan²23°)/(sin²17° + sin²73°)
=[cosec²(90°-23°) -tan²23°]/[sin²(90°-73°) +sin²73°]
=(sec²23° - tan²23°)/(cos²73° + sin²73°)
=1/1
=1
Step-by-step explanation:
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