Math, asked by s1anjanammush, 1 year ago

Find value of cosec2 67- tan2 23/ sin2 17 + sin2 73

Answers

Answered by qais
15
(cosec²67°- tan²23°)/(sin²17° + sin²73°)
=[cosec²(90°-23°) -tan²23°]/[sin²(90°-73°) +sin²73°]
=(sec²23° - tan²23°)/(cos²73° + sin²73°)
=1/1
=1

kvnmurty: good
Answered by Anonymous
2

Answer:

(cosec²67°- tan²23°)/(sin²17° + sin²73°)

=[cosec²(90°-23°) -tan²23°]/[sin²(90°-73°) +sin²73°]

=(sec²23° - tan²23°)/(cos²73° + sin²73°)

=1/1

=1

Step-by-step explanation:

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