Question

find value of discriminant
$x ^{2} + 2x = 0$
​

Answer 1

Given :-

• Equation = x² + 2x = 0

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To find :-

• Discriminant of the equation.

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Solution :-

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We have an equation x² + 2x = 0, and need to find discriminant.

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• As we know

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★ D = b² - 4ac

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Here,

• a = 1
• b = 2
• c = 0

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→ Discriminant = b² - 4 × a × c

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→ Discriminant = (2)² - 4 × 1 × 0

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→ Discriminant = 4 - 0

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→ Discriminant = 4

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Hence,

• Discriminant of the given equation is 4.

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⛦ Quadratic formula

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$\: \: \: \: \: \: \: \: \bullet\bf\: \: \: {x = \dfrac{-b \pm \sqrt{D}}{2a}}$

Answer 2

Equation:-

$x {}^{2} + 2x = 0$

As we know "D" discimint = (D)= b²-4ac.

so,

a=1( as coefficients of x² here is 1)

b=2

c=0 ( not given so we generally..take..c=0)

by using discriminat formula

(D)=b²-4ac

(D) =2²-4(1)(0)

(D)= 4-0

(D)= 4

so in that case here your D =4

Some general information:-

(i) if Discriminant is greater than zero then roots are real.

(ii) if Discriminant is equal to zero than roots are equal.

(iii) if Discriminant is not greater than zero then roots are not real.

so' in above case your "D" is euqal to 4.

therefore D > 0

4 > 0

☆ Roots are real.

$\sf\red{hope\:it\:helps\:you}$