Find value of hypotenuse if base and perpendicular are 4 and 3cm continuously?
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The hypotenuse is 5 cm
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Hey there!!!
Length of base is 4cm and perpendicular is 3cm.
Now hypotenuse =?
⇒ (H)² = (B)² + (P)²
⇒ (H)² = (4)² + (3)²
⇒ (H)² = 16 + 9
⇒ H = √25
⇒ H = √(5)²
⇒ H = 5
Therefore length of hypotenuse is 5cm.
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Hope it helps!!!
Length of base is 4cm and perpendicular is 3cm.
Now hypotenuse =?
⇒ (H)² = (B)² + (P)²
⇒ (H)² = (4)² + (3)²
⇒ (H)² = 16 + 9
⇒ H = √25
⇒ H = √(5)²
⇒ H = 5
Therefore length of hypotenuse is 5cm.
====================
Hope it helps!!!
Pintu1223:
Your method is impressive.
thnx :)
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