Question

find value of k -4 is zero of polynomial x2-x-(2k+2)

Answer 1

x-4=0x=4p(x)= x^2-x-2k+2p(4)= 4^2-4-2k+2 = 16-4-2k+2 = 12-2k+2 14-2k=0 2k= 14 k= 14/2k = 7

Answer 2

Answer:

9

Step-by-step explanation:

p(x) = x² - x - [ 2k + 2 ]

     

p(-4) =  [-4]² - [-4] - [ 2k + 2 ]

        = 16 + 4 - 2k - 2  = 0

        = 20 - 2k - 2 = 0

        18 - 2k = 0

18 = 2k

k = 18/2

k = 9