Math, asked by palak1313, 8 months ago

Find value of k 4x^3-8kx^2+21k-12k if (x-1)is the factor

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Answered by Anonymous
3

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Answered by sksonawane34
2

Answer:

k = -4

Step-by-step explanation:

(x-1) is the factor of 4x^3-8kx^2+21k-12k

Therefore, x = 1 is a root of the eqn

put x = 1 in eqn

4 (1)^3 - 8k (1)^2 + 21k - 12k = 0

4 - 8k + 21k - 12k = 0

4 - 20k + 21k

4 + k = 0

k = -4

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