find value of k
equation has equal
2x²+ kx+2=0
Answers
Answer:
heyy hope this helps u
Step-by-step explanation:
The values of k = 4.
Given:
Quadratic equation 2x^{2}+Kx +2=02x
2
+Kx+2=0 has equal roots.7
To find:
The values of k
Explanation:
General format of quadratic equation is ax^2+bx+c =0ax
2
+bx+c=0 .
If the roots of quadratic equation is equal then,
\sqrt{b^{2} \ -\ 4ac }=0
b
2
− 4ac
=0
Where,
a = coefficient of x²
b = coefficient of x
c = constant term.
\sqrt{b^{2} \ -\ 4ac }=0
b
2
− 4ac
=0
b² - 4ac =0
Comparing the quadratic equation
2x^{2}+Kx +2=02x
2
+Kx+2=0
b = k a=2 c=2
k² - 4×2×2 = 0
k² = 16
k = \sqrt{16}
16
k = 4
Therefore, the values of k = 4 if roots are equal.
To learn more...
1. If alpha and beta are roots of quadratic equation 3x2+kx+8 and alpha/beta=2/3 then find the value of k
2. The sum of the roots of a quadratic equation is 3 while the sum of the squares of its roots is 7. find the equation.
Answer:
+ 4, - 4
Step-by-step explanation:
The equation has equal roots means,
b² - 4ac = 0
2x² + kx + 2 = 0
Here,
a = 2
b = k
c = 2
b² - 4ac = 0
k² - 4 ( 2 ) ( 2 )
k² - 16 = 0
k² = 16
k = ± 4
( or )
k = + 4, - 4