Math, asked by Anonymous, 1 year ago

Find value of K for infinite solution

2x + 3y = 7

(K - 1)x + ( K + 2)y = 3k


akshaybhardwaj447: Let's solve for k.

(k+1)(x)+(k+2)(y)=3k

Step 1: Add -3k to both sides.

kx+ky+x+2y+−3k=3k+−3k

kx+ky−3k+x+2y=0

Step 2: Add -x to both sides.

kx+ky−3k+x+2y+−x=0+−x

kx+ky−3k+2y=−x

Step 3: Add -2y to both sides.

kx+ky−3k+2y+−2y=−x+−2y

kx+ky−3k=−x−2y

Step 4: Factor out variable k.

k(x+y−3)=−x−2y

Step 5: Divide both sides by x+y-3.

k(x+y−3)x+y−3=−x−2yx+y−3

k=−x−2yx+y−3

Answer:

k=−x−2yx+y−3

Answers

Answered by Anonymous
15
hope it helps..... thanks
Attachments:

Anonymous: Now what would be the appropriate answer 7 or 5
Answered by NainaMehra
10
Hope it helps you!!!!!!!!!!!!
Attachments:

Anonymous: Thank you
NainaMehra: Welcome:-)
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