Find value of K for infinite solution
2x + 3y = 7
(K - 1)x + ( K + 2)y = 3k
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hope it helps..... thanks
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Now what would be the appropriate answer 7 or 5
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Hope it helps you!!!!!!!!!!!!
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Similar questions
(k+1)(x)+(k+2)(y)=3k
Step 1: Add -3k to both sides.
kx+ky+x+2y+−3k=3k+−3k
kx+ky−3k+x+2y=0
Step 2: Add -x to both sides.
kx+ky−3k+x+2y+−x=0+−x
kx+ky−3k+2y=−x
Step 3: Add -2y to both sides.
kx+ky−3k+2y+−2y=−x+−2y
kx+ky−3k=−x−2y
Step 4: Factor out variable k.
k(x+y−3)=−x−2y
Step 5: Divide both sides by x+y-3.
k(x+y−3)x+y−3=−x−2yx+y−3
k=−x−2yx+y−3
Answer:
k=−x−2yx+y−3