Question

find value of k for real and equal roots of 9x²+3kx+4=0​

Answer 1

ATQ

IT HAS EQUAL ROOTS I.E DETERMINANT=0

therefore,

b²=4ac

9k²=4*4*9

k²=16

k= ±4

Hope it helps

Answer 2

Answer:

9k^2= 4×4×9

9k^2 = 16×9

k^2 = 144/9

k^2 = 12^2/3^2

k = root (12^2/3^2) root and square cancel

k = 12/3

k = 4/3

hope this helps you

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