Math, asked by kaurhasneet1191, 1 year ago

Find value of k for which following terms in ap 2k+1,ksquare+k+1 , 3k square-3k+3

Answers

Answered by mysticd
32
Solution :

Let a = 2k+1 , b = k²+k+1 , c =3k²-3k+3

are in A.P

b - a = c - b [ common difference ]

=> (k²+k+1)-(2k+1)=(3k²-3k+3)-(k²+k+1)

=> k²+k+1-2k-1 = 3k²-3k+3-k²-k-1

=> k²-k = 2k²-4k+2

=> 0 = 2k²-4k+2-k²+k

=> k² - 3k +2 = 0

=> k² - 2k - k + 2 = 0

=> k( k - 2 ) - ( k - 2 ) = 0

=> ( k - 2 )( k - 1 ) = 0

=> k - 2 = 0 or k - 1 = 0

=> k = 2 or k = 1

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Answered by meghajose202011
8

Answer:

look at the attachment for the answer

Step-by-step explanation:

mark brainiest

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