Question

find value of k for which polynomial kx square + x + k has equal zeros​

Answer 1

Answer:

k = 1/2  [OR]  k = -1/2

Step-by-step explanation:

$y = kx^2 + x + k$  has equal roots, i.e.,

y = 0 has equal roots.

Equal roots condition:

Discriminant = d  = (Coefficient of x)square - 4(Coefficient of x square)(Constant) = 0

i.e.,

b square - 4ac = 0

1 - 4(k)(k) = 0

4k square = 1

k square = 1/4

This implies,

k = 1/2  [OR]  k = -1/2

Hope it is useful...