Question

find value of k for which the distance between the point A (K,2) and b(9,8) is 10 unit​

Answer 1

Answer:

k=1

step by step explanation:-

Distanse between AB=√(x2-x1)²+(y2-y1)²

(AB)²=(x2-x1)²+(y2-y1)²

(10)²=(9-k)²+(8-2)²

100=(9-k)²+(6)²

100 =(9-k)²+36

100-36=(9-k)²

64=(9-k)²

(9-k)=√64

9-k=8

k=9-8

k=1.