Question

find value of k for which the point (-1,3) lies on the graph of the equation 2x-y+k=0 class 9 cbse

Answer 1

Answer:

k=5

Step-by-step explanation:

given,

2x-y+k=0

substitute the points (-1,3).we get,

2(-1)-(3)+k=0

-2-3+k=0

-5+k=0

k=5

Answer 2

Answer:

K=-5

Step-by-step explanation:

X=-1,Y=3

2(-1)-3+K=0

-2-3+k=0

5+k=0

k=0-5

k=-5