Question

find value of k for which the quadratic equation x^2+k(2x+k-1)+2=0 has equal roots​

Answer 1

Answer:

the value of k is 2✓2

b^2-4ac=0

k^2-4*1*2=0

k^2-8=0

k^2=8

k=✓8

k=✓4*2

k=2✓2