Question

find value of k if 3x-12 is factor of
$3 {x}^{2} + k \sqrt{2x} + k$
please give full solution​

Answer 1

Step-by-step explanation:

given that 3x-12 is facto of given polynomial

so put x=12/3

x=4 in given polynomial

3x^2+k√2x+k

3(4)^2+k√2(4)+k=0

3(16)+4√2k+k=0

48+k+4√2k=0

k(4√2+1)=-48

k=-48/(4√2+1)

k=-48(4√2-1)/(16×2-1)

k=-48(4√2-1)/31

hope you understand