Question

Find value of k, if (a – 1) is factor of

i) p(a) = ka^2 – 3a + k​

Answer 1

Answer:

Value of k is 3/2.

Step-by-step explanation:

Given,

(a – 1) is factor of  p(a) = ka^2 – 3a + k​.

or, a  - 1 = 0

or, a = 1

p(a) = ka^2 – 3a + k​.

0 = k(1)² - 3(1) + k

2k = 3

k = 3 / 2

Therefore, Value of k is 3/2.

Answer 2

✯ Question:

$\dashrightarrow$ Find value of k, if (a-1) is factor of p(a) = $\sf{ka^2-3a+k}$.

✯To Find:

$\dashrightarrow$ Value of k = ?

✯ Solution:

Let us find the value of a,so we get:

$\: \: \: \: \: \: \: \: \: \bullet \: \sf{a - 1 = 0} \implies \: a = 1$

Putting the value of a,

$\: \: \: \: \: \: \: : \implies \sf{p(1) = k(1)^{2} - 3(1) + k}$

$\: \: \: \: \: \: \: : \implies \sf{ \: \: \: \: \: \: \: \: \: \: = k - 3+ k}$

$\: \: \: \: \: \: \: \: \: : \implies \sf{ \: \: \: \: \: \: \: \: \: = \: 2k - 3}$

$\: \: \: \: \: \: \: \: \: : \implies \sf{2k = - 3}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies \sf \bold{k = \frac{ - 3}{2} }$

Thus,The value of k is $\sf{\frac{-3}{2}}$.