Find value of k, if (a – 1) is factor of
i) p(a) = ka^2 – 3a + k
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Ur Answer
k = 3/2
Ur Explanation :-
Ifx - 1 is the factor of the equation then
putx = 1 in these equation
(1) x+x+k = 0 (1)? +1+k=0
1+1+k = 0~k =-2
(ii) 2x+kx + v2 = 02(1)* + k(1) +
2=0 2+k+v2= 0 k =-2-
V2
(ii) kx2- V2x +1 =0>k(1))
V2(1) + 1 = 0k- V2+1=0k ==
V2-1
(iv) kx - 3x +k = 0 k(1)? - 3(1)+
k =0 k-3+ k = 0 2k =-3 »
k = 3/2
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