Question

Find value of k if kx(x-2)+6=0

Answer 1

Answer:

k=√2

Step-by-step explanation:

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Answer 2

Answer:

value of  $k =0,6$

Step-by-step explanation:

The given quadratic equation is not in the general form.

First, write the given quadratic equation in the general form.

$kx(x-2)+6=0\\kx^{2} -2kx+6=0 ..............................(1)$

On comparing given quadratic equation with the general form

$ax^{2} +bx+c=0$

Then, we have   $a=k , b= (-2k), c=6$

Find the value of discriminant $b^{2}-4ac$

$b^{2}-4ac = (-2k)^2 - 4*k*6\\b^{2}-4ac = 4k^2-24k$

Let, the roots of given quadratic are equal. Then

Put the discriminant equal to zero, We get

$b^{2}-4ac = 0\\4k^2-24k=0$

divide by 4 on both sides, we get

$k^2-6k=0$

Taking k common on left side, we get

Either $k(k-6)=0\\k=0$

Or $k-6=0\\k=6$

Therefore value of  $k =0,6$.