Question

Find value of k,if one of the roots of the quadratic equation x2-k2+12=0is 3

Answer 1

Answer:

x2 - k2 +12 = 0

let the second zeroes be you

then

3 • y = 12/1

y = 4

3 + y = k

3 + 4 = k

k = 7 Ans.

Answer 2

Answer:

k = √21.

Step-by-step explanation:

p(x) = x²-k²+12 = 0.

If we substitute x with its zero, then the value of p(x) will be equal to zero.

Therefore p(3) = 3²-k²+12 = 0.

-k² = -21

k = √21.

Hence the value of k is √21.

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