find value of k,if p(x)=2x^3-kx+3x+10 is divisible by x+2
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substitute the value of x as -2 in the equation and you will get the value of k. here , u will be substituting the value of x as -2 b'coz
x+2=0
x=(-2)
((2(-2)^3)-(k(-2))+(3(-2))+10)=0
(-16+2k-6+10)=0
(2k-12)=0
2k=12
k=6
x+2=0
x=(-2)
((2(-2)^3)-(k(-2))+(3(-2))+10)=0
(-16+2k-6+10)=0
(2k-12)=0
2k=12
k=6
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