Find value of K if quadratic equation has equal roots
A)x²-2k-6=0
Fast plz
bammidigovinda:
route 6
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this is your answer...
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Hey mate here is your answer---
x²-2k-6=0( has equal roots)
its mean D=0
a=1, b=-2k,c=-6
D=b²-4ac
0=(-2k)²- 4*1*(-6)
0=4k²+24
4k²=-24
k²=-6
k=_+√6
I think it is the answer
x²-2k-6=0( has equal roots)
its mean D=0
a=1, b=-2k,c=-6
D=b²-4ac
0=(-2k)²- 4*1*(-6)
0=4k²+24
4k²=-24
k²=-6
k=_+√6
I think it is the answer
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