find value of K if Root 5 is zero
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Solution:
p(x) = 5x³-√5x²+8kx+√180
It is given that √5 is a root of
p(x).
Now ,
p(√5) = 0
=> 5(√5)³-√5(√5)²+8k(√5)+6√5=0
=> 25√5-5√5+8√5k+6√5=0
=> 26√5 + 8√5 k = 0
=> 8√5k = -26√5
=> k = (-26√5)/8√5
=> k = -13/4
••••
yuvraj4645:
thnk yu
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