Question

find value of k if the equation x²-2(k+1)x+k²=0 has equal roots​

Answer 1

Answer:

-1/2

Step-by-step explanation:

For equal roots the formula is

b^2-4ac=0

a=1

b= -2(k+1) = -2k-2

c= k^2

So..

(-2k-2)^2 -(4)(1)(k^2)=0

(-2k)^2 + (-2)^2 +2(-2k)(-2) - 4k^2 = 0

4k^2 + 4 + 8k - 4k^2 = 0

(4k^2 and -4k^2 get cancelled)

Therefore.....

4 + 8k = 0

8k = 0-4

k = -4/8 = -1/2