Find value of k if the points -2,5 and -5,-10and k,-13 are collinear
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Sol:
A(-2,5)
B(-5,-10)
C(K,-13) are Collinear
=1/2(X1(Y2-Y3)+ X2(Y3-Y1)+X3(Y1-Y2)
1/2(-2(-10-(-13))+(-5)(-13-5)+K(5-(-10))
1/2(-2(-10+13))-5(-18)+k(5+10)
1/2(-2(+3))+90+k(15)
1/2(-6+90+15k)
1/2(84+15k)=0
84=15k
84/15=K
K=6
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