Question

find value of K if (x-2) is a factor of Kx²-x+√2​

Answer 1

Answer:

k= $-\sqrt{2}$/-2

Step-by-step explanation: (x-2) is a factor of kx^2-x+$\sqrt{2\\}$

x-2 = 0

x= 2

putting the value of x as 2

k*(2)^2-2+$\sqrt{2\\}$

= k*4-2+$\sqrt{2\\}$

= k*2+$\sqrt{2}$

= k*2 = -$\sqrt{2}$

k = $-\sqrt{2}$/-2