Question

find value of k ,if (x-2) is a factor of polynomial . p(x) = 2x³-3k+√2​

Answer 1

Answer:

$\sf{k = \frac{16 - \sqrt{2}}{3}}$

Given :

x - 2 is the factor of p(x) = 2x³ - 3k + √2

Step-by-step explanation:

p(x) = 2x³ - 3k + √2

g(x) = x - 2 = 0

⇒ x = 2

∴  p(2) = 2 × (2)³ - 3k + √2

          = 16 - 3k + √2

⇒ 3k = 16 - √2

 $\implies \sf{k = \frac{16 - \sqrt{2}}{3}}$