Question

find value of k if x=2,y=3is a solution of (k+1)x-(2k+3)y-1=0

Answer 1

k=-2..................................

Answer 2

Answer:

(k+1)x-(2k+3)y-1=0

now put the value of x and y.....so,

(k+1)2-(2k+3)3-1=0

2k+2-9-6k-1=0

2k-6k+2-9-1=0

-4k-7-1=0

-4k-8=0

4k=-8

k=-8/4=-2