Question

find value of k if x=2,y=3is a solution of (k+1)x-(2k+3)y-1=0

Answer 1

Hey There..
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Its Given that x=2
y=3 is solution,
on putting values,

(k+1)x-(2k+3)y-1=0

2k+2-6k-9-1=0

-4k-8=0

-4k=8

k=8/-4

k=-2

Hence, Value of K is -2
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Hope This Helps...!!!

:-)

Answer 2

Hey Friend ☺

x = 2 ; y = 3

( k + 1 )x - ( 2k + 3 )y - 1 = 0

》( k + 1 )2 - ( 2k + 3 )3 - 1 = 0

》2k + 2 - 6k - 9 - 1 = 0

》- 4k - 8 = 0

》- 4k = 8

》k = - 2