Question

find value of k if x minus 1 is factor of k x square - 3 x + x dk

Answer 1

$\huge{\boxed{\mathbb{ANSWER\::-}}}$

♦ As provided in the question

$f(x) = kx^2 - 3x + 2kx$ ( as the question contains some typing mistake so I will consider xdk as x2k or 2kx )

$g(x) = x - 1$

♦ In the question it is given that $f(x)$ is divisible by $g(x)$

♦ By further solving $g(x)$

$g(x) = x -1 = 0 \\\\ = x = 1$

♦ Now as we have got the value of x = 1 then by substituting value of x in $f(x)$

$f(1) = k(1)^2 - 3(x) + 2k(1) = 0$

$\implies k - 3 + 2k = 0$

$\implies 3k - 3 = 0$

$\implies 3k = 3$

$\implies k = \dfrac{3}{3}$

$\implies k =1$

♦ So if my guess about the question is correct then the value of k = 1