Question

find value of k in kx(x-2)+6=0
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Answer 1

Answer:

kx(x-2)+6=0

Step-by-step explanation:

kx²-2kx+6=0

if its a quadratic equation we can use :

b²-4ac=0

a=k,b= -2k,c=6

by subbing values of a,b and c

(-2k)²-4 x k x 6

4k²-24k=0

by common,

4k(k-6)=0

4k=0

k=0

or

k-6=0

k=6

k cannot be 0 because zero does not form a quadratic equation

but k can be 6

therefore, k=6