Question

- Find value of 'k' in kx²+8x+1=0 if it has two equal roots​

Answer 1

Answer:

D=0

b^2-4ac=0

8^2-4×k×1=0

64-4k=0

64=4k

64/4=k

16=k

Answer 2

$\rm\huge\blue{\underline{\underline{ Question : }}}$

Find the value of k in kx² + 8x + 1 = 0 if it has two equal roots.

$\rm\huge\blue{\underline{\underline{ Solution : }}}$

★ Given that,

• kx² + 8x + 1 = 0, has two equal roots.

★ To find,

• Value of k.

★ Forms used :

• $\sf\green{ :\implies Displacement = b^{2} - 4ac }$

★ Let,

• a = k
• b = 8
• c = 1

Substitute the values.

$\bf\:\implies (8)^{2} - 4(k)(1) = 0$

$\bf\:\implies 64 - 4k = 0$

$\bf\:\implies 64 = 0 + 4k$

$\bf\:\implies 4k = 64$

$\bf\:\implies k = \frac{64}{4}$

$\bf\:\implies k = 16$

$\underline{\boxed{\bf{\purple{ \therefore The\:value\:of\:K = 16.}}}}\:\orange{\bigstar}$

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★ More Information :

$\rm\red{:\implies D < 0,no \: real \: roots. }$

$\rm\red{:\implies D = 0,two \: equal \: real \: roots. }$

$\rm\red{:\implies D > 0,two \: distinct \: real \: roots. }$

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