find value of k in quadratic equation
x^2-2kx-k=0
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Answer:
Explanation:
x
2
kx+5k=0
0=0 for equal roots
b
2
−4ac=0
(2−k)
2
−4(1)(5k)=0
4k
2
(k−5)=0
k=0 or k=5
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