Math, asked by sahed3941, 1 year ago

Find value of k or which kx+3y=k-2,12x+ky=k has no solution

Answers

Answered by Anonymous
16

Answer:

Step-by-step explanation:

We know that,

For no solution, a1/a2 = b1/b2

Here,

a1 = k , b1 = 3

a2 = 12 , b2 = k

= a1/a2 = b1/b2

= k/12 = 3/k

= k² = 12 × 3

= K² = 36

= k = 6

Hence,

K = 6.

Answered by krishtiwari07
1

Answer:

By solving the given Quadratic equation...

The value of k is 6

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