Question

find value of k so that Kx(3-4x)+9=0 has equal roots ​

Answer 1

Answer:

Kx(3-4x)+9=0

3kx-4kx²+9=0

4kx²-3kx-9=0

a=4k, b=-3k c=-9

if roots are equal then b²-4ac=0

(-3k)²-4(4k)(-9)=0

9k²+144k=0

9(k²+16)=0

k²+16=0

k²=-16

k= 4 or -4