Question

Find value of k so that the sum of root of quadratic equation 3x^2 + (2k+1)x + 5 - k = 0 is equal to the product of roots

Answer 1

sum of roots= -b/a... then -(2k+1)/3... eq1

product= c/a.... 5-k/3.....eq2

from 1 and 2 equations

-(2k+1)=5-k

-2k-1=5-k

-2k+k=5+1

-k=6.. there fore...

k= -6

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