Question

find value of k so they have equal roots. (k+1)x+1=0

Answer 1

Answer:

k= -1,-1

Step-by-step explanation:

(k+1)x+1=0

given they have equal roots so,the discriminant is b^2 -4ac =0

from the equation (k+1)x+1=0

a= 0

b= (k+1)

c= 1

b^2 -4ac =0

0= (k+1) ^2 -4(0)(1)

0= (k+1) ^2

(k+1) (k+1)= 0

k= -1 ,-1

Answer 2

Answer:

1/4

Step-by-step explanation:

(k + 1)x + 1 = 0

kx + x + 1 = 0

If an equation has 2 equal roots,

then their discriminant will be equal to zero.

i.e, b$^2$ - 4ac = 0

1$^2$ - 4 (k) (1) = 0

1 - 4k = 0

1 = 4k

k = 1/4

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