Question

Find value of k such that the polynomial x2-(k+6)x+2(2k-1)

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given : $x^2-(k+6)x+2(2k-1)$

and sum of its zeroes are equal to the half of their product

To find : The value of k

Step-by-step explanation:

let the roots be $\alpha , \beta$

then

the sum of the roots are

$\alpha+\beta = k+6..(1)\\\\\text{product of roots}\\\\\alpha\beta = 4k-2..(2)$

then

according to the question

$\alpha+\beta =\frac{\alpha\beta}{2}\\\\k+6= 2k-1\\\k-2k = -1-6\\\\-k=-7\\\\k=7$

hence the value of k is 7

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