Find value of K when distance between (3,2k) and (4,1) is root 10 unit
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Answer:
A(3,2K) AND B(4,1)
√(x2-x1)∧2+(y2-y1)∧2=10
√(4-3)+(1-2k)=10
1+1-2k=10
2+2k=10
2(1+k)=10
(1+k)=10/2
1+k=5
k=5-1
k=4
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Aaj Hello mate here is your answer
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