Question

find value of k which the points (7,2)(5,1)(3,k) are collinear​

Answer 1

Answer:

k=5/2

Step-by-step explanation:

x1=7, x2=5 and x3= 3

y1=2, y2=1 and y3= k

for collinear

Area of ∆=o

1/2{x1(y2-y3) + x2(y3-y1) + x3(y1-y2)} =0

1/2{7(1-k) + 5(k-1) + x3(2-1)}=0

1/2{7-7k + 5k-5 + 3*1}=0

1/2(5-2k)=0

5-2k=0

-2k=-5

2k=5

k=5/2