Find value of log 10x/y^2 if log x = m + n and log y = m - n
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Answered by
1
Log x/y^2 =log 10+log x-2 log y
=1+m+n-2(m-n)=1+3n-m
=1+m+n-2(m-n)=1+3n-m
Answered by
9
Given:
log x = m + n and log y = m – n
Let's consider:
log 10x/y²,
log 10x/y² = log 10x – log y²
[Using log a m/n = log a m – loga n]
= log 10x – 2log y
= log 10 + log x – 2 log y
= 1 + (m + n) – 2 (m – n)
= 1 + m + n – 2m + 2n
= 1 + 3n – m
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