Math, asked by nandu1729, 9 months ago

Find value of log 128 base to 8

Answers

Answered by saisidharth84
2

Answer:

Log8128=Log(128) ÷ Log(8)

Log(128)= 2.10720996965

Log(8)=0.903089986992

Log8128=2.10720996965 ÷ 0.903089986992

Ans=2.33333333333

Answered by pulakmath007
0

\displaystyle \sf{  log_{8}(128)  } =  \frac{7}{3}

Given :

\displaystyle \sf{  log_{8}(128)  }

To find :

The value of the expression

Solution :

LStep 1 of 2 :

Write down the given expression

The given expression is

\displaystyle \sf{  log_{8}(128)  }

Step 2 of 2 :

The value of the expression

\displaystyle \sf{  log_{8}(128)  }

\displaystyle \sf{  =  \frac{log \: 128}{log \: 8} }

\displaystyle \sf{  =  \frac{log \:  {2}^{7} }{log \:  {2}^{3} } }

\displaystyle \sf{  =  \frac{7 \: log \:  2 }{3 \: log \: 2} }

\displaystyle \sf{  =  \frac{7 }{3 } }

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