Question

find value of log 243 base root 3​

Answer 1

Answer:

ans is 5

as 243 is 3^5

pls see the ans In pic

Answer 2

The value of $\log_{\sqrt3}243=10$

Step-by-step explanation:

We have been given that

$\log_{\sqrt3}243$

Use the base change formula for logarithm $log_b a=\frac{\log a}{\log b}$

$\frac{\log 243}{\log \sqrt3}$

We can write 243 as shown below

$\frac{\log 3^5}{\log \sqrt3}$

Use the formula $\log x^y=y\log x$

$\frac{5\log 3}{\log \sqrt3}$

Write 3 in exponent form

$\frac{5\log (\sqrt3)^2}{\log \sqrt3}$

Again apply the formula  $\log x^y=y\log x$

$\frac{5\cdot2\log \sqrt3}{\log \sqrt3}\\\\=\frac{10\log \sqrt3}{\log \sqrt3}\\\\=10$

Therefore, we have

$\log_{\sqrt3}243=10$

#Learn More:

Find the value of X in logarithm

brainly.in/question/3543409