Math, asked by Pratyushkar, 11 months ago

find value of log 256 to the base 64​

Answers

Answered by omprakashsahoo16
0

Answer:

log

64

(

256

)

=

x

Rewrite the equation as

x

=

log

64

(

256

)

.

x

=

log

64

(

256

)

Logarithm base

64

of

256

is

4

3

.

Tap for fewer steps...

Rewrite as an equation.

log

64

(

256

)

=

x

Rewrite

log

64

(

256

)

=

x

in exponential form using the definition of a logarithm. If

x

and

b

are positive real numbers and

b

does not equal

1

, then

log

b

(

x

)

=

y

is equivalent to

b

y

=

x

.

64

x

=

256

Create expressions in the equation that all have equal bases.

(

2

6

)

x

=

2

8

Rewrite

(

2

6

)

x

as

2

6

x

.

2

6

x

=

2

8

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

6

x

=

8

Solve for

x

.

x

=

4

3

The variable

x

is equal to

4

3

.

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Factor

2

out of

8

.

x

=

2

(

4

)

6

Cancel the common factors.

Tap for fewer steps...

Factor

2

out of

6

.

x

=

2

4

2

3

Cancel the common factor.

x

=

2

4

2

3

Rewrite the expression.

x

=

4

3

The result can be shown in multiple forms.

Exact Form:

x

=

4

3

Decimal Form:

x

=

1.

¯

3

Mixed Number Form:

x

=

1

1

3

Answered by govindashekhar566
0

Answer:

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