Question

Find value of m if (x+2) is a factor of x3-2mx2+16

Answer 1

Answer:

if (x+2) is a factor of p(x) then p(-2)=0

p(-2) =( -2)^3-2m(-2)^2+16

therefore, -8-8m+16=0

-8m = -8

m= -8/-8 = 1

Answer 2

Answer:

If (x+2) is a factor then,

p(-2)= (-2)^3-2m(-2)^2+16

0 = -8-2m4+16

0 =8-8m

m = -8/-8

m=1

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