find value of M when n=2 in the equation 7m+3n-4m=27
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Answer:
The value of m will be 7.
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7m+3n-4m=27
so,
as we know n=2
So when we will put the value
7m+3×2-4m=27
Here,
7m-4m+3×2=27
3m+6=27
3m=27-6
3m=21
m = 21/3
Therefore,
m= 7
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Hope it helps
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