Math, asked by AnshGoel2004, 11 months ago

find value of n, 3n² - n - 1430 = 0​

Answers

Answered by rutvikpatel80
3

Answer:

(n-22).(3n+65)

Step-by-step explanation:

(3n²-n)-1430

     -4290   +   1   =   -4289     -2145   +   2   =   -2143     -1430   +   3   =   -1427     -858   +   5   =   -853     -715   +   6   =   -709     -429   +   10   =   -419     -390   +   11   =   -379     -330   +   13   =   -317     -286   +   15   =   -271     -195   +   22   =   -173     -165   +   26   =   -139     -143   +   30   =   -113     -130   +   33   =   -97     -110   +   39   =   -71     -78   +   55   =   -23     -66   +   65   =   -1  

                     3n2 - 66n + 65n - 1430

                    3n • (n-22)

     65 • (n-22)

(3n+65)  •  (n-22)

             

Answered by hansraj1092007
0

Answer:

Distribute

(

3

2

3

5

7

+

1

0

6

2

)

{\color{#c92786}{n(3n^{2}-357n+1062)}}

n(3n2−357n+1062)

3

3

3

5

7

2

+

1

0

6

2

{\color{#c92786}{3n^{3}-357n^{2}+1062n}}

3n3−357n2+1062n

Solution

3

3

3

5

7

2

+

1

0

6

2

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