Question

find value of n when P(n+1,4)= 2 P(n,4)​

Answer 1

Answer:

Step-by-step explanation:

n+1P4 = 2[nP4]

(n+1)!/(n-3)! = 2[n!/(n-4)!]

(n+1)n(n-1)(n-2) = 2[n(n-1)(n-2)(n-3)]

(n+1) = 2(n-3)

n+1 = 2n - 6

2n - n = 1 + 6

n = 7

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